x^2-250x+625=0

Solution for x^2-250x+625=0 equation:

x^2-250x+625=0

a = 1; b = -250; c = +625;
Δ = b2-4ac
Δ = -2502-4·1·625
Δ = 60000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{60000}=\sqrt{10000*6}=\sqrt{10000}*\sqrt{6}=100\sqrt{6}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-250)-100\sqrt{6}}{2*1}=\frac{250-100\sqrt{6}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-250)+100\sqrt{6}}{2*1}=\frac{250+100\sqrt{6}}{2}
$